Question

An investor has an account with stock from two different companies. Last year, his stock in Company A was worth $2500 and his stock in Company B was worth $3600. The stock in Company A has increased 23% since last year and the stock in Company B has increased 14%. What was the total percentage increase in the investor's stock account? Round your answer to the nearest tenth (if necessary).

Answer 1

The one above is right hope it helps

Answer 2

well, let's take a peek, let's increase A by 23% and B by 14%

`\begin{array} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{23\% of 2500}}{\left( \cfrac{23}{100} \right)2500}\implies 575~\hfill \stackrel{2500+575 }{\text{\LARGE 3075}} \\\\\\ \stackrel{\textit{14\% of 3600}}{\left( \cfrac{14}{100} \right)3600}\implies 504\hspace{5em}\stackrel{ 3600+504 }{\text{\LARGE 4104}}`

so he had a stock of 2500 + 3600 = 6100, now it ballooned to 3075 + 4104 = 7179, so it increased by 7179 - 6100 = 1079.

if we take 6100(origin amount) as the 100%, what is 1079 off of it in percentage?

`\begin{array}{ccll} Amount&\%\\ \cline{1-2} 6100 & 100\\ 1079& x \end{array} \implies \cfrac{6100}{1079}~~=~~\cfrac{100}{x} \\\\\\ 6100x=107900\implies x=\cfrac{107900}{6100} \implies x= \cfrac{1079}{61}\implies {\Large \begin{array}{llll} x\approx 17.7 \end{array}}`