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Henry correctly factored 42? + 52 - 6 as (4% - 3)(₴ + 2)

• He then claimed that the zeros of that quadratic function are located at
*=-=
and r = 2 . Did Henry correctly find the zeros of the function?
O Yes, Henry correctly found the zeros of the function.
O No, the zeros of the function are at x = 4 and =-2
• No, the zeros of the function are at z = - 5 andx = 2.
• No, the zeros of the function are at & = 4 and ≥ = -2


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Please help

Henry correctly factored 42? + 52 - 6 as (4% - 3)(₴ + 2) • He then claimed that the-example-1
User Vpathak
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1 Answer

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28 votes

Answer:

No, the zeros of the function are at x = 3/4 and x = 2

Explanation:

the equation

4x² + 5x – 6 = 0

(note: since there is a coefficient of x² we need to multiply it to the last term(6))

4x² + 5x – 24 = 0

the factors are :- 8x and – 3x

4x² + 8x – 3x – 6 = 0

4x( x + 2) –3( x + 2) = 0

( 4x – 3)( x + 2) = 0

the zeros will be

4x – 3 = 0

4x = 3


x = (3)/(4)

x + 2 = 0

x = – 2

the zeros are x= 3/4 or –2

i hope this helps

User Hemanth Kondapalli
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