Answer:
D
Explanation:
To find the center and radius of a circle given its equation, we need to rewrite the equation in the standard form (x - a)^2 + (y - b)^2 = r^2, where (a,b) are the coordinates of the center and r is the radius.
So, let's complete square for x and y terms:
x^2 + 14x + y^2 + 2y + 14 = 0
x^2 + 14x + 49 - 49 + y^2 + 2y + 1 - 1 + 14 = 0
(x + 7)^2 + (y + 1)^2 = 36
Comparing this equation with the standard equation, we get the center at (-7, -1) and radius as sqrt(36) = 6 units.
So, the correct answer is option D: (-7, -1), 6 units.