72.2k views
1 vote
10. a record player rotates at 45 rpm. how fast in m/s is a speck of dust 4.0 cm from the axis of rotation moving?

1 Answer

3 votes

Answer:

The speed of the speck of dust would be approximately 0.188 m/s

Step-by-step explanation:

We can use the formula:

v = ωr

where:

v = linear velocity

ω = angular velocity

r = distance from the axis of rotation

Firstly, we need to convert the angular velocity from rpm to rad/s. We can do this by multiplying the rpm value by 2π/60, which is the conversion factor for rpm to rad/s:

ω = 45 rpm × 2π/60 = 4.71 rad/s

Next, we can add the calculated values into the formula:

v = ωr = (4.71 rad/s)(0.04 m) = 0.1884 m/s

Rounding up to 3 decimal places, the speck of dust is moving at approximately 0.188 m/s.

User Chris Hanson
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.