Question

15. Calculate the [OH-] and the [H+] of a substance that has a pOH of

9.45.


16. Using Kw = 1.0 x 10-14, calculate the [OH-] if the [H+ ] is 8.7 x 10-4.



17. Using Kw = 1.0 x 10-14, calculate the [H+] if the [OH-] is 2.4 x 10-9.



Answer all 3 please!! Thank you!!

Answer 1

15: [H+] = 2.82 x 10^-5 M [OH-] = 3.55 x 10^-10 M

16: [OH-] = 1.15 x 10^-11 M

17: [H+] = 4.17 x 10^-6 M

Explanation for 15: To find [OH-], we can use the formula pOH = -log[OH-]. Solving for [OH-] gives [OH-] = 3.55 x 10^-10 M. To find [H+], we can use the fact that Kw = [H+][OH-] = 1.0 x 10^-14 at 25°C. Solving for [H+] gives [H+] = 2.82 x 10^-5 M.

Explanation for 16: We can use the formula Kw = [H+][OH-] to solve for [OH-]. Rearranging the formula gives [OH-] = Kw/[H+]. Plugging in the value of Kw and [H+] gives [OH-] = 1.15 x 10^-11 M.

Explanation for 17: We can use the formula Kw = [H+][OH-] to solve for [H+]. Rearranging the formula gives [H+] = Kw/[OH-]. Plugging in the value of Kw and [OH-] gives [H+] = 4.17 x 10^-6 M.