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Write the equation of a line perpendicular to7x-8y=-5 that passes through the point ​(-7​,3​).

User Ardila
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1 Answer

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Explanation:

7x-8y = - 5 arrange to y = mx+ b form m is the slope of this line

8y = 7x+5

y = 7/8 x = 5/8 <====== m, slope = 7/8

perpendicular slope = - 1/m = - 8/7

Now use point ( -7,3) slope (-8/7) form:

y-3 = - 8/7 ( x - - 7) simplify

y = -8/7 x + 5 re-arrange , add 8/7 x to both sides of the equation

8/7 x + y = 5 multiply through by 7 to get integer values

8x + 7y = - 35

User Chocolateboy
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