Question

Find the first partial derivatives of the function. f(x, y) ax + by CX + dy fy(x, y) x(bx - ad) (cx + dy)2 x(bx - ad) (cx + dy) (bx – ad) (cx + dy)2 none

Answer 1

The first partial derivative of f(x,y) with respect to x is:

∂f/∂x = a(bx - ad) + c(cx + dy)

The first partial derivative of f(x,y) with respect to y is:

∂f/∂y = b(cx + dy) + c(cx + dy)