Question

A 75 kg baseball player runs at a velocity of 6 m/s and sliding 2 m what is the force of friction that acts upon him?

Answer 1

1350N

Step-by-step explanation:

Given data

mass= 75kg

velocity= 6m/s

distance= 2m

The expression for the applied force is given as

F= mv^2/d

Substitute

F= 75*(6)^2/ 2

F= 75*36/2

F= 2700/2

F= 1350N

Hence the force is 1350N