Question

what atomic or hybrid orbital on be makes up the sigma bond between be and br in beryllium bromide , bebr2 ?

Answer 1

The sigma bond in BeBr2 between Be and Br is formed by the overlap of an sp hybrid orbital on Be with a singly occupied orbital on Br, as a result of the sp hybridization of Be to achieve a linear electron-pair geometry.

Step-by-step explanation:

The atomic or hybrid orbital on Be that makes up the sigma bond between Be and Br in beryllium bromide (BeBr2) is an sp hybrid orbital. In BeBr2, beryllium undergoes sp hybridization to accommodate the linear electron-pair geometry as predicted by the VSEPR theory. The process involves promoting one of the 2s electrons to an empty 2p orbital, and then mixing the 2s and one 2p orbital to form two equivalent sp hybrid orbitals that are oriented 180° apart. Each sp hybrid orbital is then half-filled with a single valence electron from beryllium, allowing it to overlap with a singly occupied orbital from a bromine atom, forming a sigma bond.

Answer 2

The sigma bond between Be and Br in BeBr₂ is formed through the overlap of a hybrid orbital on Be with an orbital on Br. The hybridization of Be in this case is sp hybridization, resulting in the formation of two sp hybrid orbitals. These orbitals can form an electron-pair bond with Br, creating a linear BeBr₂ molecule.

Step-by-step explanation:

The sigma bond between Be and Br in beryllium bromide (BeBr₂) is formed by the overlap of a hybrid orbital on Be with an orbital on Br. In this case, the hybridization of Be is sp hybridization, which results in the formation of two sp hybrid orbitals. Each of these sp hybrid orbitals on Be can form an electron-pair bond with an orbital on Br. Since the two sp hybrid orbitals are oriented at a 180° angle, the BeBr₂ molecule is linear.