219k views
5 votes
Please help help help with number 6!

Please help help help with number 6!-example-1
User Souldzin
by
8.6k points

1 Answer

6 votes

Answer:

Q6. x = 8.1 ***

Q7 x = 27.87

***For question 6: Your picture of question 6 is so blurred I could not really make out the angle; I took it as 36° . If it is something else, use the formula given below with the correct angle and compute **

Explanation:

In right triangle, with one of the angles = θ , the following relationships hold


\cos \theta = (adjacent)/(hypotenuse)\\\\\sin\theta = (opposite)/(hypotenuse)\\\\\tan\theta = (opposite)/(adjacent)\\

where

adjacent means side adjacent to θ
opposite means side opposite to θ

In the given figure in Q6,

θ = 36° (I had difficulty making out the picture)

adjacent = x

hypotenuse = 10

so


\cos 36^\circ = (x)/(10)\\\\x = 10 \cdot \cos 36^\circ\\\\x = 10 \cdot 0.809\\\\x = 809\\\\\text{x = 8.1 rounded to the nearest tenth}

I have answered question 7 also since it is very similar:


\sin 35^\circ = (16)/(x)\\\\x = (16)/(\sin 35^\circ)\\\\\\= (16)/(0.574)\\\\\\= 27.8745\\\\= 27.87 \text{ to the nearest hundredth\\}

User YYY
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories