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Y intercepts of f((x)=x^{2}+2x-3

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Answer:

The y-intercept is -3

Written as a point it is (0, -3)

Explanation:

To find the y-intercept, let x = 0

(and to find x-intercepts, let y = 0)

So let's let x = 0

f(x) = x^2 + 2x - 3

y = x^2 + 2x - 3

y = 0^2 + 2(0) - 3

y = -3

This means the y-intercept is -3. The graph crosses the y-axis at -3. This is the point (0, -3).

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