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One leg of a right triangle is 14 cm shorter than the other leg. The hypotenuse of the triangle must be at least 26 cm. What can be the smallest length of the longer
leg?

User Isepise
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1 Answer

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Let x be the length of the longer leg of the right triangle. Then the shorter leg is x - 14.

According to the Pythagorean Theorem, the length of the hypotenuse c is given by:

c^2 = a^2 + b^2

where a and b are the lengths of the legs of the right triangle.

Substituting the given values, we get:

c^2 = x^2 + (x-14)^2

Expanding and simplifying, we get:

c^2 = 2x^2 - 28x + 196

Since we know that the hypotenuse must be at least 26 cm, we can write:

c^2 >= 26^2

c^2 >= 676

Substituting the expression for c^2 from above, we get:

2x^2 - 28x + 196 >= 676

Simplifying and solving for x, we get:

2x^2 - 28x - 480 >= 0

x^2 - 14x - 240 >= 0

(x - 24)(x + 10) >= 0

The solutions to this inequality are x >= 24 or x <= -10. Since x represents a length, we can ignore the negative solution. Therefore, the smallest length of the longer leg is 24 cm.
User Satish Shinde
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