Question

The width of a rectangle is w feet. The length of the rectangle is six less than three times

the width. Write an algebraic expression that represents the area, in square feet, of the
rectangle in terms of w.

Answer 1

Area = 3w^2 - 6w

Explanation:

Area = width * length

width = w

length = 3w - 6

• this is because the length is six less than three times the width so you get that the length = 3w - 6

Area = w (3w - 6)

Area = 3w^2 - 6w

Answer 2

Area of rectangle = 3w² - 6w

Explanation:

Framing algebraic expressions:

Width = 'w' ft

three times of width = 3*w = 3w

six less than 3w = 3w - 6

length = 3w - 6

`\sf \boxed{\bf Area \ of \ rectangle = length*width}`

= (3w - 6)*w

= 3w*w - 6*w

= 3w² - 6w