Answer: 15466 J
Explanation: The image quality is low, but I am assuming that you have 100.0mL of water at 0.0C and it is being raised to 37.0C.
You use the following formula:
(Temperature change)(Heat capacity)(Grams of Water) = J heat
So, you would substitute values like this:
(37)(4.18)(100) = J heat
We get 100g of water because 100 mL of water is equivalent to 100g of water. 37 is the change in temperature.
This equation evaluates to 15466 J