Answer:
Let x be the amount invested at 9% and y be the amount invested at 6%
.According to the problem:
x + y = 11,335 ----(1) (the total amount invested is $11,335)0.09x - 0.06y = 865.35 ----(2) (the interest earned from the amount invested at 9% exceeds the interest earned from the amount invested at 6% by $865.35)
We can use these two equations to solve for x and y.
Multiplying equation (1) by 0.06, we get
:0.06x + 0.06y = 680.10 ----(3)
Subtracting equation (3) from equation (2), we get:
0.03x = 185.25
x = 6,175
Substituting x = 6,175 into equation (1), we get:
y = 5,160
Therefore, $6,175 is invested at 9% and $5,160 is invested at 6%.
Explanation: