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Perform the indicated operations. Assume that no denominator has a value of 0.

2a+6/a^2+6a+9+1/a+3

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To perform the indicated operations for the expression (2a+6)/(a^2+6a+9) + 1/(a+3), we first need to find a common denominator. The denominators of the two fractions are (a^2+6a+9) and (a+3). To get a common denominator, we can multiply the first fraction by (a+3)/(a+3), which gives:

(2a+6)/(a^2+6a+9) * (a+3)/(a+3) + 1/(a+3)

= (2a+6)(a+3)/(a+3)(a^2+6a+9) + (a^2+6a+9)/(a+3)(a^2+6a+9)

= (2a^2+12a+18+a^2+6a+9)/(a^2+6a+9)(a+3)

= (3a^2+18a+27)/(a+3)(a^2+6a+9)

= 3(a+3)(a+3)/(a+3)(a+3)(a+1)

= 3/(a+1)

Therefore, the simplified form of the expression is 3/(a+1).

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