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Find an equation of the circle that has center (-1, 6) and passes through (-5, 1).

User Mahima
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1 Answer

3 votes

Answer:

(x + 1)² + (y - 6)² = 50

Explanation:

The circle's standard form equation is

(x - h)² + (y - k)² = r²

where the radius is r and the center's coordinates are (h, k).

The radius is the distance a point on a circle travels from its center.

Apply the distance formula to determine the variable r.

R is equal to sqrt(x_2 - x_1) +(y_{2}-y_{1})^2 }

and (x2, y2) = (-6, 1) with (x1, y1) = (-1, 6)

r = \sqrt{(-6+1)^2+(1-6)^2}

= \sqrt{(-5)^2+(-5)^2}

= \sqrt{25+25}

= \sqrt{50}

If (h, k) = (-1, 6)

(x - (- 1))² + (y - 6)² = (\sqrt{50} )2, which is

(x + 1)2 + (y - 6)2 = 50 is the circle's equation.

User Whymarrh
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