Question

5. A stock solution of sodium fluoride (NaF) has a concentration of 6.00M. How many liters of this solution would you need to dilute to produce 3.25L of 1.00M NaF?

Answer 1

0.542L

Step-by-step explanation:

this requires the dilution formula
`M_(1) V_(1) = M_(2) V_(2)` where

M1 = initial concentration

V1 = initial volume

M2 = final concentration

V2 = final volume

In this case, we are solving for V1 where M1 = 6.00M, M2 = 1.00M, and V2 = 3.25L.

Plugged into the equation we get:

(6.00M) V1 = (1.00M)(3.25L)

divide both sides by 6.00M and it becomes (M cancel)

V1 =
`((1.00M)(3.25L))/((6.00M))` = 0.542L