Question

PLEASE ANSWER QUICKLY!!!!! 50 POINTS

2KI(aq) + Cl₂(g) → 2KCI(aq) + 1₂ (g)
44.8 L 12 forms at STP. How many moles of KI were required for the
reaction?
?] mol KI

Answer 1

It took about 3.74 moles of KI to complete the reaction.

The reaction between chlorine gas and potassium iodide is what kind?

Solid iodine (I2) and potassium chloride are produced when chlorine (Cl2) gas is passed through an aqueous solution of potassium iodide (KI) (KCl). This is a displacement reaction in which the more reactive chlorine displaces the less reactive iodine in potassium iodide.

n = PV/RT

where V is the volume, T is the temperature, and R is the gas constant. The temperature and pressure are both 1 atm at STP. By replacing these values, we obtain:

n = (1 atm) * (44.8 L) / (0.0821 L·atm/mol·K * 273 K) ≈ 1.87 mol I₂

We know that the number of moles of KI needed for the reaction is twice the number of moles of I2 produced since 1 mole of I2 is created for every 2 moles of KI.

n(KI) = 2 * n(I₂) ≈ 3.74 mol KI