We wish to determine the
moles of lead (II) iodide
precipitated when 125 mL of
0.20 M potassium
iodide reacts with excess
lead (II) nitrate.
2Kl(aq) + Pb(NO3)2(aq) → 2KNO3(aq) + Pbl₂(s)
How many moles of KI are
present in 125 mL of 0.20 M KI?
[?] mol KI