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10 votes
10 votes
2 A bag contains three red counters, four green counters, two yellow counters and one white

counter. Two counters are drawn from the bag one after the other, without being replaced.
Calculate:
a P(two red counters)
b P(two green counters)
c P(two yellow counters)
d P(white and then red)
e P(white or yellow, in either order but not both)
f P(white or red, in either order but not both).
g What is the probability of drawing a white or yellow counter first and then any colour second?

User Brian DiCasa
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1 Answer

20 votes
20 votes

Answer: P(WY)=1/10*2/9=1/45

P(YW)=2/10*1/9=1/45

P(WY or YW)=2/45

Also 2C1*1C1/10C2=2×1/45=2/45

2/5

Explanation:

User Vladyslav Khromykh
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2.7k points