Question

g 8. A hydrogen atom is initially a rest and in the ground state. A proton with kinetic energy 1000 eV scatters off the atom. In the process the hydrogen atom is ionized. The kinetic energy of the ionized electron is measured to be 15.2 eV and the kinetic energy of the proton produced from the ionization of hydrogen is 4.3 eV. What would be the final kinetic energy of the projectile proton after the collision

Answer 1

Step-by-step explanation:

Ionization energy of hydrogen atom is 13.6 eV . This energy will be provided by energetic proton , the kinetic energy of which is 1000 eV. The kinetic energy of ionized electron is 15.2 eV . Kinetic energy of proton produced from from the ionization of hydrogen or the nucleus of the hydrogen atom is 4.3 eV . All these energy must have come from kinetic energy of initial proton.

So kinetic energy of projectile proton after collision

= 1000 - ( 13.6 + 15.2 + 4.3 ) eV.

= 966.9 eV .