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A child bounces a 48 g superball on the side- walk. The velocity change of the superball is from 22 m/s downward to 17 m/s upward. 1 If the contact time with the sidewalk is 800 s, what is the magnitude
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3 votes
A child bounces a 48 g superball on the side-

walk. The velocity change of the superball is

from 22 m/s downward to 17 m/s upward.

1

If the contact time with the sidewalk is

800

s, what is the magnitude of the average force

exerted on the superball by the sidewalk?

User Saket Mittal
by
8.5k points

1 Answer

3 votes

Answer:

0,3

Step-by-step explanation:

force = mass ×accelaration

User Simon Ninon
by
7.9k points
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