Question

The length of a rectangle is 10 meters more than twice its width. What are the dimensions of the rectangle if its perimeter is 62 m? I​

Answer 1

Let x be the width of the rectangle. Then the length of the rectangle is 2x + 10.

The perimeter of the rectangle is the sum of the lengths of all four sides, which is:

P = 2L + 2W = 2(2x + 10) + 2x = 6x + 20

We know that P = 62, so we can set up an equation and solve for x:

62 = 6x + 20

Subtracting 20 from both sides gives:

42 = 6x

Dividing both sides by 6 gives:

x = 7

So the width of the rectangle is 7 meters. The length of the rectangle is 2x + 10 = 2(7) + 10 = 24 meters.

Therefore, the dimensions of the rectangle are 7 meters by 24 meters.