Question

Find the direction of this vector.

O = [?]°

80.0°

B<18.6 m

Hint: Remember, o is the direction of the

vector and is measured from the +x-axis.


i need help

Answer 1

To find the direction of a vector given its components in the x and y direction, we can use the inverse tangent function (tan^-1) of the ratio of the y-component to the x-component.

In this case, we have the vector B with a magnitude of 18.6 m and a direction of 80.0° from the +x-axis. We can break down this vector into its x and y components using trigonometry:

Bx = B cos(80.0°) = -3.62 m

By = B sin(80.0°) = 18.3 m

Note that we have used the negative sign for Bx because the vector makes an angle of 80.0° with the +x-axis in the clockwise direction.

Now we can find the direction of the vector O, which is given by the inverse tangent of the ratio of the y-component to the x-component:

O = tan^-1(By/Bx) = tan^-1(-18.3/-3.62) = 79.1°

Therefore, the direction of the vector O is 79.1° from the +x-axis.