Answer:
A square pyramid has 5 faces: 1 square base and 4 triangular faces.
The area of the base is:
A = s^2
where s is the length of the base edge.
In this case, s = 1 m, so:
A = 1^2 = 1 m^2
The area of each triangular face is:
A = 1/2 * b * h
where b is the base of the triangle (which is equal to the length of one side of the square base) and h is the height of the triangle (which is given as 1 m).
In this case, b = 1 m and h = 1 m, so:
A = 1/2 * 1 * 1 = 0.5 m^2
The total surface area of the pyramid is the sum of the area of the base and the area of the four triangular faces:
SA = A_base + 4 * A_triangles
SA = 1 + 4(0.5)
SA = 1 + 2
SA = 3 m^2
Therefore, the surface area of the pyramid is 3 square meters.