130k views
1 vote
The table shows the population of Center City in various years. Use the data from 1990 and 2005 to create a linear model that predicts the population of the city (y) in a given year (x). In which year was the actual population of Center City most different from the value predicted by this model?

2 Answers

3 votes

To create a linear model, we can use the formula for the equation of a line:

y = mx + b

where m is the slope and b is the y-intercept. We can calculate the slope using the formula:

m = (y2 - y1)/(x2 - x1)

Let's use the data from 1990 and 2005:

x1 = 1990, y1 = 210,000

x2 = 2005, y2 = 320,000

m = (320,000 - 210,000)/(2005 - 1990) = 11,000

Now we can use the point-slope form of a line to find the y-intercept:

y - y1 = m(x - x1)

y - 210,000 = 11,000(x - 1990)

y - 210,000 = 11,000x - 21,790,000

y = 11,000x - 21,580,000

So the linear model that predicts the population of Center City (y) in a given year (x) is:

y = 11,000x - 21,580,000

To find the year when the actual population of Center City was most different from the value predicted by this model, we can compare the actual population to the predicted population for each year and find the year with the largest difference.

Year | Actual Population | Predicted Population | Difference

1990 | 210,000 | 188,000 | 22,000

1995 | 240,000 | 239,000 | 1,000

2000 | 280,000 | 290,000 | 10,000

2005 | 320,000 | 341,000 | 21,000

We can see that the actual population was most different from the predicted population in 2005, with a difference of 21,000.

User Oscar Broman
by
7.7k points
6 votes

Answer: c (year 2000)

Step-by-step explanation: blud above got me confused

User ELTA
by
7.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories