Answer:
20.0°C
Step-by-step explanation:
To find the final temperature of the water after it has transferred thermal energy to the ice cube, we need to use the equation:
Q = cmΔT
where Q is the amount of thermal energy transferred, c is the specific heat capacity of the substance, m is the mass of the substance, and ΔT is the change in temperature.
In this case, we are given that Q = 4,200 J and m = 200 g. The specific heat capacity of water is 4.184 J/g°C.
Substituting these values into the equation gives us:
4,200 J = (4.184 J/g°C)(200 g)(ΔT)
Solving for ΔT gives us:
ΔT = 4,200 J / [(4.184 J/g°C)(200 g)] = 10°C
Since the initial temperature of the water was 10.0°C, the final temperature of the water is 10.0°C + 10°C = 20.0°C.
Therefore, the temperature of the water in the glass is 20.0°C after it has transferred 4,200 J of thermal energy to the ice cube.