Question

There are 5 white balls, 8 red balls, 7 yellow balls and 4 green balls in a container. A ball is chosen at random. What is the probability of choosing neither white nor green

Answer 1

The probability is 5/8

Explanation:

First, we must add all the numbers together. 5 + 8 + 7 + 4 = 24. Now, let's add the white balls and green balls. 5 + 4 = 9. Therefore, the probability of choosing a white or green ball is 9/24 which also equals 3/8. To find out the probability of NOT choosing white or green, we must subtract 9 from 24. 24 - 9 = 15. So, the probability of choosing neither the white or green balls equals 15/24 which also equals 5/8.

Hope this helps!!

Answer 2

Answer: 5/8

Explanation:

i just added all of them & took out the white and green balls ......... oh and i also simplified it