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A line that contains the point 0,-8 with a slope of 3/2

User Retief
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Answer:

The equation of the line that contains the point (0, -8) with a slope of 3/2 is y = (3/2)x - 8.

Explanation:

We can use the point-slope form of a linear equation to write an equation for the line that contains the point (0, -8) with a slope of 3/2:

y - y1 = m(x - x1)

where m is the slope, and (x1, y1) is the given point on the line. Substituting the given values, we get:

y - (-8) = (3/2)(x - 0)

Simplifying and rearranging, we get:

y + 8 = (3/2)x

y = (3/2)x - 8

Therefore, the equation of the line that contains the point (0, -8) with a slope of 3/2 is y = (3/2)x - 8.

User Kingindanord
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