Answer:
The equation of the line that contains the point (0, -8) with a slope of 3/2 is y = (3/2)x - 8.
Explanation:
We can use the point-slope form of a linear equation to write an equation for the line that contains the point (0, -8) with a slope of 3/2:
y - y1 = m(x - x1)
where m is the slope, and (x1, y1) is the given point on the line. Substituting the given values, we get:
y - (-8) = (3/2)(x - 0)
Simplifying and rearranging, we get:
y + 8 = (3/2)x
y = (3/2)x - 8
Therefore, the equation of the line that contains the point (0, -8) with a slope of 3/2 is y = (3/2)x - 8.