Question

Blossom, the WonderDog, is ambling along at 1.1m/s when she sees a villainous squirrel

enter the yard. If Blossom continuously accelerates at 0.4m/s/s for 3.8 seconds before she
reaches her prey, how far did she travel?

Answer 1

7.068m

Step-by-step explanation:

We have the physics formula
`x=x_(0)+v_(0)t+(1)/(2)at^(2)`

`v_(0)=` 1.1m/s

`x_0=` 0m

`a=` 0.4m/s²

`t=` 3.8sec

Now we plug those values into the formula.

`x=0+1.1(3.8)+(1)/(2)0.4 (3.8)^(2)`

`x=4.18+0.2(14.44)`

`x=4.18+2.888`

`x=7.068`m

Blossom traveled 7.068m.

Hope this helps!