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6. the temperature of the ch3oh is increased from 300 k to 400 k to vaporize all the liquid, which increases the pressure in the vessel to 0.30 atm. the experiment is repeated under identical conditions but this time using half the mass of ch3oh that was used originally. what will be the pressure in the vessel at 400 k ?

User Josh Close
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2 Answers

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Final answer:

The pressure in the vessel at 400 K when using half the mass of CH3OH will be half of the original pressure, thus resulting in a pressure of 0.15 atm.

Step-by-step explanation:

The given scenario involves vaporizing methanol (CH3OH) by increasing its temperature, which in turn increases the pressure in the vessel. Initially, the pressure increases to 0.30 atm at 400 K. When the experiment is repeated with half the mass of CH3OH under identical conditions, the pressure in the vessel at 400 K can be determined using the ideal gas law and assuming that the volume and the amount of substance are directly proportional to pressure at constant temperature (Gay-Lussac's law).

Since the mass of CH3OH used in the second experiment is half of the original, and assuming the volume of the vessel and the temperature remain constant, the pressure will also be half. Therefore, the pressure in the vessel at 400 K with half the mass of CH3OH will be 0.15 atm.

User Sudeep Juvekar
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4 votes

Final answer:

If the experiment is repeated with half the mass of CH3OH, the pressure in the vessel at 400 K will still be 0.30 atm.

Step-by-step explanation:

When the temperature of CH3OH is increased from 300 K to 400 K, the pressure in the vessel increases to 0.30 atm. If the experiment is repeated with half the mass of CH3OH, the pressure in the vessel at 400 K can be calculated using the idea gas law.

According to the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. Since the number of moles (n) is proportional to the mass, if we use half the mass of CH3OH, we will have half the number of moles.

Therefore, the pressure in the vessel at 400 K with half the mass of CH3OH will also be 0.30 atm.

User Xavier Noria
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