Final answer:
If the experiment is repeated with half the mass of CH3OH, the pressure in the vessel at 400 K will still be 0.30 atm.
Step-by-step explanation:
When the temperature of CH3OH is increased from 300 K to 400 K, the pressure in the vessel increases to 0.30 atm. If the experiment is repeated with half the mass of CH3OH, the pressure in the vessel at 400 K can be calculated using the idea gas law.
According to the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. Since the number of moles (n) is proportional to the mass, if we use half the mass of CH3OH, we will have half the number of moles.
Therefore, the pressure in the vessel at 400 K with half the mass of CH3OH will also be 0.30 atm.