Answer:
When an object is thrown straight up near the surface of the Earth, the net force acting on it is the force of gravity (weight) minus the force of air resistance (if present).
Assuming that air resistance is negligible, the net force acting on the object is equal to its weight, which is given by:
F = m * g
where F is the force, m is the mass of the object, and g is the acceleration due to gravity near the surface of the Earth.
The value of g is approximately 9.8 m/s^2, which means that the net force on the object is equal to its weight of m * 9.8 m/s^2.
As the object moves upward, its velocity decreases due to the force of gravity, until it reaches its maximum height and its velocity becomes zero at the top of its trajectory. At this point, the net force on the object is momentarily zero, since its velocity is not changing and the force of gravity is balanced by the force of the object's upward motion.
As the object falls back to the ground, the net force acting on it is once again its weight, but this time it is acting in the opposite direction to the direction of the object's motion.
Step-by-step explanation:
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