Question

5. What is the buoyant force on a 7.9 x 102 m³ anvil that is floating in mercury? The density

of mercury is 13500 kg/m³.

hurry i’m taking a test

Answer 1

fb = 1.05×10^8

Step-by-step explanation:

`fb = pvg`

where Fb is the buoyant force in Newtons

ρ is the density of the fluid in kilograms per cubic meter

V is the volume of displaced fluid in cubic meter &

g is the acceleration due to gravity.

Given

p = 13500 kg/m³

V = 7.9 x 10^2 m³ = 790 m3

g = 9.81m/s^2

soln

fb = pvg

fb = ( 13500 kg/m³)(790 m³)(9.81m/s^2 )

fb = 104, 623, 650 approximate to 1.05×10^8

so bouyant force is 1.05×10^8