What’s the x and y to this

Question

asked Feb 19, 2024 19.1k views

1 Answer

Joshua Owoyemi · Answer 1 · 2024-02-24T03:10:08+0000

$\huge\begin{array}{ccc}y=-(3)/(2)x+3\end{array}$

The "point-slope" form of the equation of a straight line:

POINTS:

$(x_1,\ y_1),\ (x_2,\ y_2)$

EQUATION:

y-y_1=m(x-x_1)

where

SLOPE:

m=(y_2-y_1)/(x_2-x_1)

We have two points whose coordinates can be read from the graph:

$(0,\ 3),\ (2,\ 0)$

Substitute:

$m=(0-3)/(2-0)=(-3)/(2)=-(3)/(2)\\\\y-3=-(3)/(2)(x-0)\\\\y-3=-(3)/(2)x$

add 3 to both sides

$y-3+3=-(3)/(2)x+3}\\\\\boxed{y=-(3)/(2)x+3}$