Question

methyl alcohol (ch3oh)is made by the reaction of carbon monoxide and hydrogen in the presence of certain metal oxide catalysts. how much alcohol can be obtained by reaction of 35.5 g of co and 9.06 of h2?

Answer 1

The balanced chemical equation for the synthesis of methyl alcohol (CH3OH) from carbon monoxide (CO) and hydrogen (H2) is:

CO + 2H2 → CH3OH

To determine how much methyl alcohol can be obtained from the given amounts of CO and H2, we need to first convert the given masses into moles using their molar masses:

Molar mass of CO = 28.01 g/mol

Molar mass of H2 = 2.02 g/mol

Moles of CO = 35.5 g CO / 28.01 g/mol = 1.266 mol CO

Moles of H2 = 9.06 g H2 / 2.02 g/mol = 4.49 mol H2

According to the balanced equation, 1 mole of CO reacts with 2 moles of H2 to produce 1 mole of CH3OH. Therefore, the limiting reactant is CO, and the maximum amount of CH3OH that can be produced is given by the amount of CO present:

Moles of CH3OH = 1.266 mol CO × (1 mol CH3OH / 1 mol CO) = 1.266 mol CH3OH

Finally, we can convert the moles of CH3OH to grams using its molar mass:

Molar mass of CH3OH = 32.04 g/mol

Grams of CH3OH = 1.266 mol CH3OH × 32.04 g/mol = 40.6 g CH3OH

Therefore, the maximum amount of methyl alcohol that can be obtained from 35.5 g of CO and 9.06 g of H2 is 40.6 g of CH3OH.

Step-by-step explanation:

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