Question

At the Olympics, the winners of the gold, silver, and bronze medals stand on a tiered pedestal.

Assuming each pedestal is of equal width and depth, find the total surface area of the stand.

Answer 1

4320 in²

Explanation:

You want the total surface area of the 3-tiered pedestal shown in the figure.

Front area

The area of the front of the stand is that of the three 20-inch wide pedestals stacked on top of each other for a total height of 11 +15 +7 = 33 inches. That area is ...

A = LW = (20 in)(33 in) = 660 in²

Lateral area

Lateral area of the pedestal is the product of its depth (20 in) and the perimeter of the front. The front perimeter is the equivalent of the perimeter of a rectangle 60 inches wide and 15 inches high, which is ...

P = 2(60 +15 in) = 150 in

Total area

The total surface area of the stand is the sum of front and back areas and the lateral area:

SA = 660 in² +660 in² +(20 in)(150 in) = 4320 in²

The total surface area of the stand is 4320 square inches.

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Additional comment

That's 30 square feet.

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