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3 votes
Of the 100 employees at a

company, 75 are married and
57 have at least one child.
Thirty-three of the employees
married do not have any
children. If an employee is
chosen at random, find
P(has at least one child | married).

Of the 100 employees at a company, 75 are married and 57 have at least one child. Thirty-example-1
User Greg Ball
by
8.7k points

1 Answer

4 votes

Answer: 0.56

Explanation:

If 33 of the married people do not have a child, then 75 - 33 of the married people do have a child. 75 - 33 = 42.

* n = intersection (both events occur)

P At least 1 child 'given' that they are married)

= p (at least 1 child n married) / p (married)

= (42/100) / (75/100)

= 42/75

= 0.56

User Waclock
by
8.0k points

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