Question

Please help!!

Kara is setting up a tee-shirt cannon for a community event. The angle of the cannon can be adjusted, but all projectiles leave the cannon at 25 meters per second. If Kara sets the angle of the cannon to be 20 degrees above horizontal, what will be the range of the projectiles?

Answer 1

The range of the projectiles when the cannon is set at a 20 degree angle above the horizontal is 114.4 meters.

Step-by-step explanation:

To find the range of the projectiles, we can use the range formula for projectile motion. The formula is given by:

R = (v^2 * sin(2θ)) / g

Where R is the range, v is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity. In this case, the initial velocity is 25 m/s and the launch angle is 20 degrees above the horizontal.

Substituting the values in the formula:

R = (25^2 * sin(2 * 20)) / 9.8 = 114.4 meters

Therefore, the range of the projectiles will be approximately 114.4 meters.