Answer: The vertex of the parabola given by the equation y = 10x² + 4 is:
(-b/2a, f(-b/2a))
where a and b are the coefficients of the x² and x terms, respectively, in the standard form of a quadratic equation y = ax² + bx + c.
In this case, a = 10 and b = 0, so the x-coordinate of the vertex is:
-b/2a = 0/20 = 0
To find the y-coordinate of the vertex, we substitute x = 0 into the equation y = 10x² + 4:
y = 10(0)² + 4 = 4
Therefore, the vertex of the parabola is (0, 4).