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What is the vertex of the parabola

y=10x² + 4?
( ) ( )

User Eric Yang
by
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1 Answer

2 votes

Answer: The vertex of the parabola given by the equation y = 10x² + 4 is:

(-b/2a, f(-b/2a))

where a and b are the coefficients of the x² and x terms, respectively, in the standard form of a quadratic equation y = ax² + bx + c.

In this case, a = 10 and b = 0, so the x-coordinate of the vertex is:

-b/2a = 0/20 = 0

To find the y-coordinate of the vertex, we substitute x = 0 into the equation y = 10x² + 4:

y = 10(0)² + 4 = 4

Therefore, the vertex of the parabola is (0, 4).

User Bruce Seymour
by
8.1k points
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