Question

Coil of resistance 10 Ohm and inductance of 0.1 Henry is connected in

series with condenser of capacitance of 150 micro Farad across 200 V, 50
Hz, AC supply. Find current, power, power factor, voltage drop across
coil, voltage drop across condenser and draw the phasor diagram

Answer 1

Answer: Your welcome!

Step-by-step explanation:

Current I = 200/√(10^2 + (2π × 50 × 0.1)^2) = 200/√1000 = 14.14 A

Power P = I2R = 14.142 × 10 = 141.4 W

Power factor PF = cos φ = R/√(R2 + X2) = 10/√(102 + (2π × 50 × 0.1)2) = 0.99

Voltage drop across resistance VR = I × R = 14.14 × 10 = 141.4 V

Voltage drop across condenser VC = I × X = 14.14 × 2π × 50 × 0.1 = 44.18 V

The phasor diagram is shown below:

Phasor Diagram

V = 200 V at 0°

I = 14.14 A at -90°

VR = 141.4 V at 0°

VC = 44.18 V at +90°