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a tangential force of 70n applied on a solid cross sectional area 20cm^2 caused a deformation through an angle 0.003. calculate the shear modulus of elasticity of the solid​

User ZeroDotNet
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Hello

The shear modulus of elasticity (G) is given by the equation:

G = (F * L) / (A * Δx)

where F is the tangential force, L is the length of the solid, A is the cross-sectional area, and Δx is the deformation caused by the force.

In this case, F = 70 N, A = 20 cm^2 = 0.002 m^2, and Δx = L * θ, where θ is the deformation angle.

We need to find the value of G.

First, we need to find the value of L * θ. We can use the formula:

θ = Δx / L

Rearranging this formula, we get:

L * θ = Δx

We know that Δx is not given in the question, but we can calculate it using the formula:

Δx = A * G * θ / F

Substituting the given values, we get:

Δx = (0.002 m^2) * G * (0.003) / (70 N)

Simplifying this equation, we get:

Δx = 8.57 x 10^-6 m

Substituting this value into the formula for G, we get:

G = (F * L) / (A * Δx)

G = (70 N * L) / (0.002 m^2 * 8.57 x 10^-6 m)

G = 4.09 x 10^10 N/m^2

Therefore, the shear modulus of elasticity of the solid is 4.09 x 10^10 N/m^2