Hello
The shear modulus of elasticity (G) is given by the equation:
G = (F * L) / (A * Δx)
where F is the tangential force, L is the length of the solid, A is the cross-sectional area, and Δx is the deformation caused by the force.
In this case, F = 70 N, A = 20 cm^2 = 0.002 m^2, and Δx = L * θ, where θ is the deformation angle.
We need to find the value of G.
First, we need to find the value of L * θ. We can use the formula:
θ = Δx / L
Rearranging this formula, we get:
L * θ = Δx
We know that Δx is not given in the question, but we can calculate it using the formula:
Δx = A * G * θ / F
Substituting the given values, we get:
Δx = (0.002 m^2) * G * (0.003) / (70 N)
Simplifying this equation, we get:
Δx = 8.57 x 10^-6 m
Substituting this value into the formula for G, we get:
G = (F * L) / (A * Δx)
G = (70 N * L) / (0.002 m^2 * 8.57 x 10^-6 m)
G = 4.09 x 10^10 N/m^2
Therefore, the shear modulus of elasticity of the solid is 4.09 x 10^10 N/m^2