Question

4. Find the areas of the sectors formed by ZACB.
D
2 m,
C 101°
A
B

Answer 1

so I guess is getting the area of both sectors, hmmm, ok, well, one sector is 101° and the other must be 259°, both have a radius of 2.

`\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360} ~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=2\\ \theta =101 \end{cases}\implies A=\cfrac{(101)\pi (2)^2}{360}\implies A\approx 3.53~m^2 \\\\[-0.35em] ~\dotfill`

`\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360} ~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=2\\ \theta =259 \end{cases}\implies A=\cfrac{(259)\pi (2)^2}{360}\implies A\approx 9.04~m^2`