1 Answer

Serhii Rohoza · Answer 1 · 2024-01-11T04:07:16+0000

Answer:

$V = (640)/(3) \text{ ft}^3$ OR
$213\, (1)/(3) \text{ ft}^3$

Explanation:

The formula for the volume of a pyramid is:

$V = (1)/(3) \cdot A_{\text{base}} \cdot h$

First, we can find the area of the pyramid's base, which is a square.

$A_{\text{square}} = (\text{side length})^2$

$A_{\text{base}} = (8 \text{ ft})^2$

$A_{\text{base}} = 8 \text{ ft} \cdot 8 \text{ ft}$

$A_{\text{base}} = 64 \text{ ft}^2$

Then, we can plug that value into the above volume formula along with the height shown in the diagram.

$V = (1)/(3) \cdot A_{\text{base}} \cdot h$

$V = (1)/(3) \cdot 64\text{ ft}^2 \cdot 10\text{ ft}$

$V = (64)/(3) \text{ ft}^2 \cdot 10 \text{ ft}$

$\boxed{V = (640)/(3) \text{ ft}^3}$

$\boxed{V=213\, (1)/(3) \text{ ft}^3}$

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