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A dog sits 1.50 m from the center of a merry-go-round and revolves at a tangential speed of 1.80 m/s. If the dog’s mass is 18.5 kg, what is the magnitude of the centripetal force on the dog?
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11 votes
11 votes
A dog sits 1.50 m from the center of a merry-go-round and revolves at a tangential speed of 1.80 m/s. If the dog’s mass is 18.5 kg, what is the magnitude of the centripetal force on the dog?

User J Atkin
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2.8k points

1 Answer

24 votes
24 votes

Answer: Fc = 39.96 N

Step-by-step explanation:

Fc = (mv^2)/r

Fc = (18.5 kg * (1.80 m/s)^2)/(1.50 m)

Fc = 39.96 N

User Artem Andreev
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3.3k points
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