the temp increases to 371.63k or 98.48°c
p1v1/t1=p2v2/t2
cancel out p because it stays constant
0.0441L/273.15k=0.060L/t2
manipulate the equation so that t2=v2/(v1/t1)
0.060L/1.614L/k=371.63k
temperature and volume are directly proportional, if volume increases, temperature increases and vice versa