Question

A package of copper foil contains 50.0 square feet of foil and weighs approximately 44.8 oz. Copper has a density of 8.96 g/cubic cm. Which of the following represents the thickness of copper foil? Answer should be in picometers with correct number of significant figures. A. 3.05x10^7pm B. 2.03x10^7pm C. 2.03x10^3pm D. 3.04pm E. 6.97x10^4pm

Answer 1

Step-by-step explanation:

To find the thickness of the copper foil, we need to use the given information about its area, weight, and density.

First, we need to convert the weight of the foil from ounces to grams, since the density of copper is given in grams per cubic centimeter (g/cm³):

44.8 oz x (28.35 g/oz) = 1267.28 g

Next, we can use the formula for density:

density = mass / volume

to find the volume of the copper foil:

density = 8.96 g/cm³

mass = 1267.28 g

volume = mass / density = 1267.28 g / 8.96 g/cm³ = 141.34 cm³

Now we can use the area and volume of the foil to find its thickness:

area = 50.0 sq ft = 4645.15 sq cm

thickness = volume / area = 141.34 cm³ / 4645.15 sq cm = 0.0304 cm

Finally, we need to convert the thickness from centimeters to picometers, since the answer choices are given in picometers:

0.0304 cm x (10 mm/cm) x (1000 µm/mm) x (1000 nm/µm) = 304,000 pm

Rounding to the correct number of significant figures, the answer is:

304,000 pm

Therefore, the correct answer is not one of the options given.