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What proportion of a normal distribution is located between each

of the following z-scores?

z = -1. 64 and z = +1. 64

z = -1. 96 and z = +1. 96

z = -1. 00 and z = +1. 0

1 Answer

1 vote

The proportion of a normal distribution that is located between two z-scores can be calculated using a standard normal distribution table or a calculator with a normal distribution function.

For the given z-scores:

z = -1.64 and z = +1.64:

The area under the normal distribution curve between these two z-scores is the same as the area between z = 0 and z = +1.64 minus the area between z = 0 and z = -1.64. From a standard normal distribution table, the area between z = 0 and z = +1.64 is 0.4505, and the area between z = 0 and z = -1.64 is also 0.4505. Therefore, the area between z = -1.64 and z = +1.64 is:

0.4505 - 0.4505 = 0

So, there is no area between z = -1.64 and z = +1.64.

z = -1.96 and z = +1.96:

Using the same approach as above, the area under the normal distribution curve between these two z-scores is:

0.4750 - 0.4750 = 0

So, there is no area between z = -1.96 and z = +1.96.

z = -1.00 and z = +1.00:

Again, using the same approach, the area under the normal distribution curve between these two z-scores is:

0.3413 - 0.3413 = 0

So, there is no area between z = -1.00 and z = +1.00.

Therefore, for all three cases, the proportion of a normal distribution that is located between the given z-scores is 0.

User Shahrear Bin Amin
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