Question

An unknown metal at 100. 0∘C with specific heat 1. 14 Jg∘C is placed in 750. G of water at 25. 0∘C. The final temperature of the water is 28. 6∘C. What was the mass of the metal?

Round your answer to the nearest integer. Use 4. 184Jg∘C for the specific heat of water

Answer 1

heat lost by metal= heat gained by water.

M × 1.14 × 71.4= 750× 4.184 × 3.6

81.396 M = 11296.8

divide both sides by 81.396

M= 138.78

M=139 g