5.6k views
0 votes
Mercury has a mass of

3.30 x 1023 kg, and a radius of
2.44 x 106 m. What is the acceleration
of gravity on its surface?
[?] m/s² Please help!!!

User Tenwest
by
8.6k points

1 Answer

4 votes

Answer:

The acceleration due to gravity on the surface of a planet or celestial body is given by the formula:

g = G M / R^2

where G is the gravitational constant, M is the mass of the planet, and R is the radius of the planet.

Plugging in the values for Mercury, we get:

g = (6.674 x 10^-11 m^3/kg s^2) (3.30 x 10^23 kg) / (2.44 x 10^6 m)^2

Simplifying this expression gives:

g = 3.70 m/s^2

Therefore, the acceleration due to gravity on the surface of Mercury is approximately 3.70 m/s^2.

User PALEN
by
9.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.